In the given nuclear reaction,how many $\alpha$ and $\beta$ particles are emitted in the decay $_{92}X^{235} \to _{82}Y^{207}$?

Write nuclear reaction equations for:
$(i)$ $\alpha$-decay of $^{226}_{88}Ra$
$(ii)$ $\alpha$-decay of $^{242}_{94}Pu$
$(iii)$ $\beta^-$-decay of $^{32}_{15}P$
$(iv)$ $\beta^-$-decay of $^{210}_{83}Bi$
$(v)$ $\beta^+$-decay of $^{11}_{6}C$
$(vi)$ $\beta^+$-decay of $^{97}_{43}Tc$
$(vii)$ Electron capture of $^{120}_{54}Xe$

$A$ nucleus of $_{84}^{210}Po$ originally at rest emits an $\alpha$ particle with speed $v$. What will be the recoil speed of the daughter nucleus?

In the uranium radioactive series,the initial nucleus is $_{92}U^{238}$ and the final nucleus is $_{82}Pb^{206}$. When the uranium nucleus decays to lead,the number of $\alpha$-particles emitted will be

${}^{238}U$ has $92$ protons and $238$ nucleons. It decays by emitting an alpha particle and becomes:

${ }_{82}^{290} X \xrightarrow{\alpha} Y \xrightarrow{e^{+}} Z \xrightarrow{\beta^{-}} P \xrightarrow{e^{-}} Q$
In the nuclear emission stated above, the mass number and atomic number of the product $Q$ respectively, are