In the given nuclear reaction, how many $\beta$ and $\alpha$ particles are emitted $_{92}{X^{235}} \to {\;_{82}}{Y^{207}}$
$3 \alpha$ particles and $2 \beta$ particle
$4 \alpha$ particles and $3 \beta$ particle
$6 \alpha$ particles and $4 \beta$ particle
$7 \alpha$ particles and $4 \beta$ particle
The composition of an $\alpha $- particle can be expressed as
A nucleus decays by ${\beta ^ + }$ emission followed by a gamma emission. If the atomic and mass numbers of the parent nucleus are $Z$ and $A$ respectively, the corresponding numbers for the daughter nucleus are respectively.
In the given reaction $_z{X^A}{ \to _{z + 1}}{Y^A}{ \to _{z - 1}}{K^{A - 4}}{ \to _{z - 1}}{K^{A - 4}}$ Radioactive radiations are emitted in the sequence
A free neutron decays into a proton but a free proton does not decay into neutron. This is because
Write nuclear reaction equations for
$(i)$ $\alpha$ -decay of $^{226}_{88} Ra$
$(ii)$ $\alpha$ -decay of $_{94}^{242} Pu$
$(iii)$ $\beta$ -decay of $_{15}^{32} P$
$(iv)$ $\beta$ -decay of $^{210}_{83}Bi$
$(v)$ $\beta^{+}$ -decay of $_{6}^{11} C$
$(vi)$ $\beta^{+}$ -decay of $_{43}^{97} Tc$
$(vii)$ Electron capture of $^{120}_{54} Xe$